There are several ways to calculate the sides and angles of a triangle. These depend on the type of triangle you are working with.
In this opportunity, it will be shown how to calculate the sides and angles of a right triangle, assuming that certain data of the triangle with known.
The elements that will be used are:
Given a right triangle with legs "a", "b" and hypotenuse "c", it is true that "c² = a² + b²".
The formula to calculate the area of any triangle is A = (b × h) / 2, where “b” is the length of the base and “h” is the length of the height.
The sum of the three interior angles of a triangle is 180º.
Consider a right triangle. Then, the trigonometric functions sine, cosine and tangent of the angle beta (β) are defined as follows:
sin (β) = CO / Hip, cos (β) = CA / Hip and tan (β) = CO / CA.
Given a right triangle ABC, the following situations can occur:
If leg “a” measures 3 cm and leg “b” measures 4 cm, then the Pythagorean theorem is used to calculate the value of “c”. By substituting the values of "a" and "b" we obtain that c² = 25 cm², which implies that c = 5 cm.
Now, if angle β is opposite leg “b”, then sin (β) = 4/5. By applying the inverse function of the sine, in this last equality we obtain that β = 53.13º. Two internal angles of the triangle are already known.
Let θ be the angle that remains to be known, then 90º + 53.13º + θ = 180º, from which we obtain that θ = 36.87º.
In this case it is not necessary that the known sides are the two legs, the important thing is to know the value of any two sides.
Let a = 3 cm be the known leg and A = 9 cm² the area of the triangle.
In a right triangle, one leg can be considered as the base and the other as the height (since they are perpendicular).
Suppose that “a” is the base, therefore 9 = (3 × h) / 2, from which we obtain that the other leg is 6 cm. To calculate the hypotenuse, proceed as in the previous case, and we obtain that c = √45 cm.
Now, if the angle β is opposite the leg “a”, then sin (β) = 3 / √45. Solving for β it is obtained that its value is 26.57º. We only need to know the value of the third angle θ.
It is satisfied that 90º + 26.57º + θ = 180º, from which it is concluded that θ = 63.43º.
Let β = 45º be the known angle and a = 3 cm the known leg, where leg “a” is opposite angle β. Using the tangent formula, we obtain that tg (45º) = 3 / CA, from which it follows that CA = 3 cm.
Using the Pythagorean theorem we obtain that c² = 18 cm², that is, c = 3√2 cm.
It is known that an angle measures 90º and that β measures 45º, from here it is concluded that the third angle measures 45º.
In this case, the known side does not have to be a leg, it can be any of the three sides of the triangle.
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